What is the first derivative of 3+4t ?

The first derivative of 3+4t is 4

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derivative of 3+4t

derivative of

3 + 4 t

4

Solution steps

\frac{d}{d t} (3 + 4 t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3) + \frac{d}{d t} (4 t)

\frac{d}{d t} (3) = 0

\frac{d}{d t} (4 t) = 4

= 0 + 4

Simplify

= 4

x (ln (x))^{2} - e

(x^{x})^{3}

\frac{x}{x ^{3} + 1}

\frac{d}{d n} ((- i)^{4 n})

\frac{y ^{2}}{x ^{2}}