What is the derivative of x^3-3^x ?

The derivative of x^3-3^x is 3x^2-3^xln(3)

What is the first derivative of x^3-3^x ?

The first derivative of x^3-3^x is 3x^2-3^xln(3)

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derivative of

x^{3} - 3^{x}

3 x^{2} - 3^{x} ln (3)

Solution steps

\frac{d}{d x} (x^{3} - 3^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3^{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= 3 x^{2} - 3^{x} ln (3)

f (x) = - x + 2

y = \frac{x ^{2} - x + 1}{a ^{3} - 3}

y = t^{2}

\frac{sec ( x )}{x ^{2}}

\frac{d}{d t} (6 + 3 t^{2} + 2 t)

What is the derivative of x^3-3^x ?
The derivative of x^3-3^x is 3x^2-3^xln(3)
What is the first derivative of x^3-3^x ?
The first derivative of x^3-3^x is 3x^2-3^xln(3)