What is the derivative of (sec(x))/(x^2) ?

The derivative of (sec(x))/(x^2) is (sec(x)(xtan(x)-2))/(x^3)

What is the first derivative of (sec(x))/(x^2) ?

The first derivative of (sec(x))/(x^2) is (sec(x)(xtan(x)-2))/(x^3)

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derivative of

\frac{sec ( x )}{x ^{2}}

\frac{sec ( x ) ( x tan ( x ) - 2 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{sec ( x )}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( sec ( x ) ) x ^{2} - \frac{d}{d x} ( x ^{2} ) sec ( x )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

\frac{d}{d x} (x^{2}) = 2 x

= \frac{sec ( x ) tan ( x ) x ^{2} - 2 x sec ( x )}{( x ^{2} ) ^{2}}

Simplify

\frac{sec ( x ) tan ( x ) x ^{2} - 2 x sec ( x )}{( x ^{2} ) ^{2}} : \frac{sec ( x ) ( x tan ( x ) - 2 )}{x ^{3}}

= \frac{sec ( x ) ( x tan ( x ) - 2 )}{x ^{3}}

\frac{d}{d t} (6 + 3 t^{2} + 2 t)

\frac{d}{d x} (k \cdot x^{2} - 2 x + 1)

sin^{2} (x + 4)

x y + 1

\frac{sec ( y )}{y ^{2}}

What is the derivative of (sec(x))/(x^2) ?
The derivative of (sec(x))/(x^2) is (sec(x)(xtan(x)-2))/(x^3)
What is the first derivative of (sec(x))/(x^2) ?
The first derivative of (sec(x))/(x^2) is (sec(x)(xtan(x)-2))/(x^3)