What is the first derivative of xy+1 ?

The first derivative of xy+1 is y

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derivative of xy+1

derivative of

x y + 1

y

Solution steps

\frac{d}{d x} (x y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y) + \frac{d}{d x} (1)

\frac{d}{d x} (x y) = y

\frac{d}{d x} (1) = 0

= y + 0

Simplify

= y

\frac{sec ( y )}{y ^{2}}

\frac{d}{d t} (5 t^{3} - 10 t)

4^{x} + 1

\frac{d}{d a} (\frac{a ^{2} - 2 a + a}{9})

y^{2} x + 5 x y^{3} + 10 y^{2} + 8 x y