What is the derivative of (50)/((13sin(x+33.6))) ?

The derivative of (50)/((13sin(x+33.6))) is 50/13 (-1/((sin(x+33.6))^2)cos(x+33.6)*1)

What is the first derivative of (50)/((13sin(x+33.6))) ?

The first derivative of (50)/((13sin(x+33.6))) is 50/13 (-1/((sin(x+33.6))^2)cos(x+33.6)*1)

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derivative of

\frac{50}{( 13 sin ( x + 33. 6 ^{\circ} ) )}

\frac{50}{13} (- \frac{1}{( sin ( x + 33. 6 ^{\circ} ) ) ^{2}} cos (x + 33. 6^{\circ}) \cdot 1)

Solution steps

\frac{d}{d x} (\frac{50}{13 sin ( x + 33. 6 ^{\circ} )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{50}{13} \frac{d}{d x} (\frac{1}{sin ( x + 33. 6 ^{\circ} )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{50}{13} \frac{d}{d x} (sin^{- 1} (x + 33. 6^{\circ}))

Apply the chain rule:

- \frac{1}{( sin ( x + 33. 6 ^{\circ} ) ) ^{2}} \frac{d}{d x} (sin (x + 33. 6^{\circ}))

= - \frac{1}{( sin ( x + 33. 6 ^{\circ} ) ) ^{2}} \frac{d}{d x} (sin (x + 33. 6^{\circ}))

\frac{d}{d x} (sin (x + 33. 6^{\circ})) = cos (x + 33. 6^{\circ}) \cdot 1

= \frac{50}{13} (- \frac{1}{( sin ( x + 33. 6 ^{\circ} ) ) ^{2}} cos (x + 33. 6^{\circ}) \cdot 1)

\frac{e ^{- x}}{2}

\frac{d}{d t} (cos^{4} (t) - sin^{4} (t))

y = - x^{3} (3 x^{4} - 2)

(f^{- 1}) (d)

\frac{d}{d t} (\frac{( 3 t ^{2} )}{2} + \frac{t}{4} + 21)

What is the derivative of (50)/((13sin(x+33.6))) ?
The derivative of (50)/((13sin(x+33.6))) is 50/13 (-1/((sin(x+33.6))^2)cos(x+33.6)*1)
What is the first derivative of (50)/((13sin(x+33.6))) ?
The first derivative of (50)/((13sin(x+33.6))) is 50/13 (-1/((sin(x+33.6))^2)cos(x+33.6)*1)