What is the d/(dt)(cos^4(t)-sin^4(t)) ?

The d/(dt)(cos^4(t)-sin^4(t)) is -sin(2t)*2

What is the first d/(dt)(cos^4(t)-sin^4(t)) ?

The first d/(dt)(cos^4(t)-sin^4(t)) is -sin(2t)*2

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\frac{d}{d t} (cos^{4} (t) - sin^{4} (t))

- sin (2 t) \cdot 2

Solution steps

\frac{d}{d t} (cos^{4} (t) - sin^{4} (t))

Simplify

cos^{4} (t) - sin^{4} (t) : cos (2 t)

= \frac{d}{d t} (cos (2 t))

Apply the chain rule:

- sin (2 t) \frac{d}{d t} (2 t)

= - sin (2 t) \frac{d}{d t} (2 t)

\frac{d}{d t} (2 t) = 2

= - sin (2 t) \cdot 2

y = - x^{3} (3 x^{4} - 2)

(f^{- 1}) (d)

\frac{d}{d t} (\frac{( 3 t ^{2} )}{2} + \frac{t}{4} + 21)

f (x) = 0.2 x + 0.03

(\frac{3}{2})^{x}

What is the d/(dt)(cos^4(t)-sin^4(t)) ?
The d/(dt)(cos^4(t)-sin^4(t)) is -sin(2t)*2
What is the first d/(dt)(cos^4(t)-sin^4(t)) ?
The first d/(dt)(cos^4(t)-sin^4(t)) is -sin(2t)*2