What is the derivative of x^2y+1 ?

The derivative of x^2y+1 is 2xy

What is the first derivative of x^2y+1 ?

The first derivative of x^2y+1 is 2xy

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derivative of

x^{2} y + 1

2 x y

Solution steps

\frac{d}{d x} (x^{2} y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} y) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2} y) = 2 y x

\frac{d}{d x} (1) = 0

= 2 y x + 0

Simplify

= 2 x y

ln (x) ln (2 x)

\frac{d}{d x} (\frac{4}{2 x ^{2} - ( + 4 ) ( - 3 ) - ( - 6 ) ( - 2 )})

\frac{1}{n ( 1 + ln ( x ) ) ^{2}}

\frac{d}{d y} (\frac{y}{2 x + 1})

\frac{1}{n}