What is the d/(dy)(y/(2x+1)) ?

The d/(dy)(y/(2x+1)) is 1/(2x+1)

What is the first d/(dy)(y/(2x+1)) ?

The first d/(dy)(y/(2x+1)) is 1/(2x+1)

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\frac{d}{d y} (\frac{y}{2 x + 1})

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d y} (\frac{y}{2 x + 1})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2 x + 1} \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= \frac{1}{2 x + 1} \cdot 1

Simplify

= \frac{1}{2 x + 1}

\frac{1}{n}

(3 x^{2} + 7) (6 x + 3)

(x^{2} - y^{2})^{\frac{1}{2}}

y = \frac{6 t + 1}{5}

\frac{1}{( x ( ln ( x ) ) ^{p} )}