What is the derivative of (3x^2+7)(6x+3) ?

The derivative of (3x^2+7)(6x+3) is 54x^2+18x+42

What is the first derivative of (3x^2+7)(6x+3) ?

The first derivative of (3x^2+7)(6x+3) is 54x^2+18x+42

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derivative of

(3 x^{2} + 7) (6 x + 3)

54 x^{2} + 18 x + 42

Solution steps

\frac{d}{d x} ((3 x^{2} + 7) (6 x + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 3 x^{2} + 7, g = 6 x + 3

= \frac{d}{d x} (3 x^{2} + 7) (6 x + 3) + \frac{d}{d x} (6 x + 3) (3 x^{2} + 7)

\frac{d}{d x} (3 x^{2} + 7) = 6 x

\frac{d}{d x} (6 x + 3) = 6

= 6 x (6 x + 3) + 6 (3 x^{2} + 7)

Simplify

6 x (6 x + 3) + 6 (3 x^{2} + 7) : 54 x^{2} + 18 x + 42

= 54 x^{2} + 18 x + 42

(x^{2} - y^{2})^{\frac{1}{2}}

y = \frac{6 t + 1}{5}

\frac{1}{( x ( ln ( x ) ) ^{p} )}

y = 4 x + 1

y = 4 x + 7

What is the derivative of (3x^2+7)(6x+3) ?
The derivative of (3x^2+7)(6x+3) is 54x^2+18x+42
What is the first derivative of (3x^2+7)(6x+3) ?
The first derivative of (3x^2+7)(6x+3) is 54x^2+18x+42