What is the first derivative of y=4x+7 ?

The first derivative of y=4x+7 is 4

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derivative of y=4x+7

derivative of

y = 4 x + 7

4

Solution steps

\frac{d}{d x} (4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 4 + 0

Simplify

= 4

(x^{3} + 3 x^{2})^{4}

\frac{( ( x ^{6} ) - 1 )}{( ( x ^{6} ) + 1 )}

\frac{( x ^{2} + 1 )}{x}

y = 3 cos (x) + 7 e x + ln (x^{2} + 1)

f (x) = \frac{4 x - 1}{x}