What is the derivative of ((x^2+1))/x ?

The derivative of ((x^2+1))/x is (x^2-1)/(x^2)

What is the first derivative of ((x^2+1))/x ?

The first derivative of ((x^2+1))/x is (x^2-1)/(x^2)

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derivative of

\frac{( x ^{2} + 1 )}{x}

\frac{x ^{2} - 1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 1 ) x - \frac{d x}{d x} ( x ^{2} + 1 )}{x ^{2}}

\frac{d}{d x} (x^{2} + 1) = 2 x

\frac{d x}{d x} = 1

= \frac{2 xx - 1 \cdot ( x ^{2} + 1 )}{x ^{2}}

Simplify

\frac{2 xx - 1 \cdot ( x ^{2} + 1 )}{x ^{2}} : \frac{x ^{2} - 1}{x ^{2}}

= \frac{x ^{2} - 1}{x ^{2}}

y = 3 cos (x) + 7 e x + ln (x^{2} + 1)

f (x) = \frac{4 x - 1}{x}

2^{z}

y = sin (x^{- 1})

x^{2} cos (lo g_{10} (x))

What is the derivative of ((x^2+1))/x ?
The derivative of ((x^2+1))/x is (x^2-1)/(x^2)
What is the first derivative of ((x^2+1))/x ?
The first derivative of ((x^2+1))/x is (x^2-1)/(x^2)