What is the derivative of 2^z ?

The derivative of 2^z is 2^zln(2)

What is the first derivative of 2^z ?

The first derivative of 2^z is 2^zln(2)

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derivative of

2^{z}

2^{z} ln (2)

Solution steps

\frac{d}{d z} (2^{z})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2^{z} ln (2)

y = sin (x^{- 1})

x^{2} cos (lo g_{10} (x))

\frac{d}{d t} (2 t - 2)

\frac{d}{d a} (sec^{2} (a) + tan^{2} (a))

y = 5 sin (x) + 3 cos (x) + 5 x^{2}