What is the derivative of (x^3+8)/3 ?

The derivative of (x^3+8)/3 is x^2

What is the first derivative of (x^3+8)/3 ?

The first derivative of (x^3+8)/3 is x^2

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derivative of

\frac{x ^{3} + 8}{3}

x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3} + 8}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (x^{3} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d}{d x} (x^{3}) + \frac{d}{d x} (8))

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (8) = 0

= \frac{1}{3} (3 x^{2} + 0)

Simplify

\frac{1}{3} (3 x^{2} + 0) : x^{2}

= x^{2}

\frac{( x ^{2} + 3 )}{( x + 1 )}

\frac{d}{d a} (sec^{2} (a) + cos^{2} (a))

\frac{2}{( x + 3 )}

2 tan (x) + sec (x) - 3 cot (x)

\frac{x ^{3}}{3 - 3 x}

What is the derivative of (x^3+8)/3 ?
The derivative of (x^3+8)/3 is x^2
What is the first derivative of (x^3+8)/3 ?
The first derivative of (x^3+8)/3 is x^2