What is the d/(da)(sec^2(a)+cos^2(a)) ?

The d/(da)(sec^2(a)+cos^2(a)) is 2sec^2(a)tan(a)-sin(2a)

What is the first d/(da)(sec^2(a)+cos^2(a)) ?

The first d/(da)(sec^2(a)+cos^2(a)) is 2sec^2(a)tan(a)-sin(2a)

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\frac{d}{d a} (sec^{2} (a) + cos^{2} (a))

2 sec^{2} (a) tan (a) - sin (2 a)

Solution steps

\frac{d}{d a} (sec^{2} (a) + cos^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (sec^{2} (a)) + \frac{d}{d a} (cos^{2} (a))

\frac{d}{d a} (sec^{2} (a)) = 2 sec^{2} (a) tan (a)

\frac{d}{d a} (cos^{2} (a)) = - sin (2 a)

= 2 sec^{2} (a) tan (a) - sin (2 a)

\frac{2}{( x + 3 )}

2 tan (x) + sec (x) - 3 cot (x)

\frac{x ^{3}}{3 - 3 x}

arcsin (e^{x})

3^{x} + 2

What is the d/(da)(sec^2(a)+cos^2(a)) ?
The d/(da)(sec^2(a)+cos^2(a)) is 2sec^2(a)tan(a)-sin(2a)
What is the first d/(da)(sec^2(a)+cos^2(a)) ?
The first d/(da)(sec^2(a)+cos^2(a)) is 2sec^2(a)tan(a)-sin(2a)