What is the derivative of y=sin^2(x)0.2x ?

The derivative of y=sin^2(x)0.2x is 0.2(xsin(2x)+sin^2(x))

What is the first derivative of y=sin^2(x)0.2x ?

The first derivative of y=sin^2(x)0.2x is 0.2(xsin(2x)+sin^2(x))

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derivative of

y = sin^{2} (x) 0.2 x

0.2 (x sin (2 x) + sin^{2} (x))

Solution steps

\frac{d}{d x} (sin^{2} (x) \cdot 0.2 x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.2 \frac{d}{d x} (sin^{2} (x) x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sin^{2} (x), g = x

= 0.2 (\frac{d}{d x} (sin^{2} (x)) x + \frac{d x}{d x} sin^{2} (x))

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

\frac{d x}{d x} = 1

= 0.2 (sin (2 x) x + 1 \cdot sin^{2} (x))

Simplify

= 0.2 (x sin (2 x) + sin^{2} (x))

y = e^{3} x

(x^{2} + 3 x + 2)^{2} + ln (e) x^{2}

e^{2 x - 1}

\frac{1}{x ^{\frac{3}{2}}}

y = \frac{1}{( x + 3 )}

What is the derivative of y=sin^2(x)0.2x ?
The derivative of y=sin^2(x)0.2x is 0.2(xsin(2x)+sin^2(x))
What is the first derivative of y=sin^2(x)0.2x ?
The first derivative of y=sin^2(x)0.2x is 0.2(xsin(2x)+sin^2(x))