What is the derivative of y= 1/((x+3)) ?

The derivative of y= 1/((x+3)) is -1/((x+3)^2)

What is the first derivative of y= 1/((x+3)) ?

The first derivative of y= 1/((x+3)) is -1/((x+3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = \frac{1}{( x + 3 )}

- \frac{1}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - \frac{1}{( x + 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 3 ) ^{2}}

ln (2 x + 1) (e^{x})^{2}

(1 - x^{2})^{10}

x^{3} y^{4}

y = sin (x^{2} + 2 x + 3)

\frac{d}{d b} (2 b)

What is the derivative of y= 1/((x+3)) ?
The derivative of y= 1/((x+3)) is -1/((x+3)^2)
What is the first derivative of y= 1/((x+3)) ?
The first derivative of y= 1/((x+3)) is -1/((x+3)^2)