What is the d/(da)(1-8sin^2(a)cos^2(a)) ?

The d/(da)(1-8sin^2(a)cos^2(a)) is -4sin(4a)

What is the first d/(da)(1-8sin^2(a)cos^2(a)) ?

The first d/(da)(1-8sin^2(a)cos^2(a)) is -4sin(4a)

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\frac{d}{d a} (1 - 8 sin^{2} (a) cos^{2} (a))

- 4 sin (4 a)

Solution steps

\frac{d}{d a} (1 - 8 sin^{2} (a) cos^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (1) - \frac{d}{d a} (8 sin^{2} (a) cos^{2} (a))

\frac{d}{d a} (1) = 0

\frac{d}{d a} (8 sin^{2} (a) cos^{2} (a)) = 8 sin (2 a) cos (2 a)

= 0 - 8 sin (2 a) cos (2 a)

Simplify

0 - 8 sin (2 a) cos (2 a) : - 4 sin (4 a)

= - 4 sin (4 a)

(\frac{1}{5})^{x}

\frac{( x + 1 ) ( x - 2 )}{x ^{2}}

(- 1 + 2 t)^{- 1}

y = x^{3} + 2 x - 1

a^{\frac{1}{x}}

What is the d/(da)(1-8sin^2(a)cos^2(a)) ?
The d/(da)(1-8sin^2(a)cos^2(a)) is -4sin(4a)
What is the first d/(da)(1-8sin^2(a)cos^2(a)) ?
The first d/(da)(1-8sin^2(a)cos^2(a)) is -4sin(4a)