What is the derivative of y=x^3+2x-1 ?

The derivative of y=x^3+2x-1 is 3x^2+2

What is the first derivative of y=x^3+2x-1 ?

The first derivative of y=x^3+2x-1 is 3x^2+2

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derivative of

y = x^{3} + 2 x - 1

3 x^{2} + 2

Solution steps

\frac{d}{d x} (x^{3} + 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} + 2 - 0

Simplify

= 3 x^{2} + 2

a^{\frac{1}{x}}

3 ln (2 x - 1)

\frac{( 3 x ^{2} + 5 ) ^{1}}{x}

y = x^{2} ln (4 x)

lo g_{10} (∣ 3 x ∣)

What is the derivative of y=x^3+2x-1 ?
The derivative of y=x^3+2x-1 is 3x^2+2
What is the first derivative of y=x^3+2x-1 ?
The first derivative of y=x^3+2x-1 is 3x^2+2