What is the derivative of f(x)=(x+sin(x))^2 ?

The derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))

What is the first derivative of f(x)=(x+sin(x))^2 ?

The first derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))

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derivative of

f (x) = (x + sin (x))^{2}

2 (x + sin (x)) (1 + cos (x))

Solution steps

\frac{d}{d x} ((x + sin (x))^{2})

Apply the chain rule:

2 (x + sin (x)) \frac{d}{d x} (x + sin (x))

= 2 (x + sin (x)) \frac{d}{d x} (x + sin (x))

\frac{d}{d x} (x + sin (x)) = 1 + cos (x)

= 2 (x + sin (x)) (1 + cos (x))

\frac{d}{d x} (ln ((x - b)^{2}) - ln ((y - a)^{2}))

f (x) = x^{2} - 4 x + 9

e^{x} - y^{2}

\frac{d}{d t} (10 + 5 t)

\frac{2000}{x}

What is the derivative of f(x)=(x+sin(x))^2 ?
The derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))
What is the first derivative of f(x)=(x+sin(x))^2 ?
The first derivative of f(x)=(x+sin(x))^2 is 2(x+sin(x))(1+cos(x))