What is the derivative of f(x)=(3x-4)^2(x-2) ?

The derivative of f(x)=(3x-4)^2(x-2) is 27x^2-84x+64

What is the first derivative of f(x)=(3x-4)^2(x-2) ?

The first derivative of f(x)=(3x-4)^2(x-2) is 27x^2-84x+64

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derivative of

f (x) = (3 x - 4)^{2} (x - 2)

27 x^{2} - 84 x + 64

Solution steps

\frac{d}{d x} ((3 x - 4)^{2} (x - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (3 x - 4)^{2}, g = x - 2

= \frac{d}{d x} ((3 x - 4)^{2}) (x - 2) + \frac{d}{d x} (x - 2) (3 x - 4)^{2}

\frac{d}{d x} ((3 x - 4)^{2}) = 6 (3 x - 4)

\frac{d}{d x} (x - 2) = 1

= 6 (3 x - 4) (x - 2) + 1 \cdot (3 x - 4)^{2}

Simplify

6 (3 x - 4) (x - 2) + 1 \cdot (3 x - 4)^{2} : 27 x^{2} - 84 x + 64

= 27 x^{2} - 84 x + 64

(x^{2} + 2)^{- 1}

\frac{1}{( 1 + e ^{u} )}

ln ((1 + 3 x)^{2})

3 t + 4

3 t - 1

What is the derivative of f(x)=(3x-4)^2(x-2) ?
The derivative of f(x)=(3x-4)^2(x-2) is 27x^2-84x+64
What is the first derivative of f(x)=(3x-4)^2(x-2) ?
The first derivative of f(x)=(3x-4)^2(x-2) is 27x^2-84x+64