What is the derivative of tan(e^s)inx^2 ?

The derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s

What is the first derivative of tan(e^s)inx^2 ?

The first derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s

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derivative of

tan (e^{s}) in x^{2}

in x^{2} sec^{2} (e^{s}) e^{s}

Solution steps

\frac{d}{d s} (tan (e^{s}) in x^{2})

Treat

i, n, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= in x^{2} \frac{d}{d s} (tan (e^{s}))

Apply the chain rule:

sec^{2} (e^{s}) \frac{d}{d s} (e^{s})

= sec^{2} (e^{s}) \frac{d}{d s} (e^{s})

\frac{d}{d s} (e^{s}) = e^{s}

= in x^{2} sec^{2} (e^{s}) e^{s}

(1 + x)^{2 y + 1}

y = (sin (x))^{5}

(2^{x})^{2} + 1 + e^{c} os x

g (x) = 2 x + 2

sin^{4} (3 x)

What is the derivative of tan(e^s)inx^2 ?
The derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s
What is the first derivative of tan(e^s)inx^2 ?
The first derivative of tan(e^s)inx^2 is inx^2sec^2(e^s)e^s