What is the derivative of 5x^4+8 ?

The derivative of 5x^4+8 is 20x^3

What is the first derivative of 5x^4+8 ?

The first derivative of 5x^4+8 is 20x^3

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derivative of

5 x^{4} + 8

20 x^{3}

Solution steps

\frac{d}{d x} (5 x^{4} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{4}) + \frac{d}{d x} (8)

\frac{d}{d x} (5 x^{4}) = 20 x^{3}

\frac{d}{d x} (8) = 0

= 20 x^{3} + 0

Simplify

= 20 x^{3}

ln^{2} (x^{3}) - 3

(x^{2} + 2 x)^{\frac{1}{2}}

2 x^{2} + x + 5

x^{2} lo g_{10} (\frac{1}{x})

\frac{1}{( 1 - x ^{2} )}

What is the derivative of 5x^4+8 ?
The derivative of 5x^4+8 is 20x^3
What is the first derivative of 5x^4+8 ?
The first derivative of 5x^4+8 is 20x^3