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Popular >

derivative of a+b^1x^1+b^2x^2e

Solution

\frac{d}{d x} (a + b^{1} x^{1} + b^{2} x^{2} e)

Solution

2 e b^{2} x + b

Solution steps

\frac{d}{d x} (a + b^{1} x^{1} + b^{2} x^{2} e)

Simplify

a + b^{1} x^{1} + b^{2} x^{2} e : a + b x + e b^{2} x^{2}

= \frac{d}{d x} (a + b x + e b^{2} x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d a}{d x} + \frac{d}{d x} (b x) + \frac{d}{d x} (e b^{2} x^{2})

\frac{d a}{d x} = 0

\frac{d}{d x} (b x) = b

\frac{d}{d x} (e b^{2} x^{2}) = 2 e b^{2} x

= 0 + b + 2 e b^{2} x

Simplify

= 2 e b^{2} x + b

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Frequently Asked Questions (FAQ)

What is the derivative of a+b^1x^1+b^2x^2e ?
The derivative of a+b^1x^1+b^2x^2e is 2eb^2x+b
What is the first derivative of a+b^1x^1+b^2x^2e ?
The first derivative of a+b^1x^1+b^2x^2e is 2eb^2x+b