What is the derivative of x^2+sin(x)+1 ?

The derivative of x^2+sin(x)+1 is 2x+cos(x)

What is the first derivative of x^2+sin(x)+1 ?

The first derivative of x^2+sin(x)+1 is 2x+cos(x)

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derivative of

x^{2} + sin (x) + 1

2 x + cos (x)

Solution steps

\frac{d}{d x} (x^{2} + sin (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (sin (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (1) = 0

= 2 x + cos (x) + 0

Simplify

= 2 x + cos (x)

f (x) = 2 + 31 n (x - 4 x + 1)

(e^{x})^{\frac{1}{2}}

cot^{4} (x)

y = 6 x^{- 2}

\frac{1}{( z - 1 )}

What is the derivative of x^2+sin(x)+1 ?
The derivative of x^2+sin(x)+1 is 2x+cos(x)
What is the first derivative of x^2+sin(x)+1 ?
The first derivative of x^2+sin(x)+1 is 2x+cos(x)