What is the derivative of 2/((s^2+4)) ?

The derivative of 2/((s^2+4)) is -(4s)/((s^2+4)^2)

What is the first derivative of 2/((s^2+4)) ?

The first derivative of 2/((s^2+4)) is -(4s)/((s^2+4)^2)

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derivative of

\frac{2}{( s ^{2} + 4 )}

- \frac{4 s}{( s ^{2} + 4 ) ^{2}}

Solution steps

\frac{d}{d s} (\frac{2}{s ^{2} + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d s} (\frac{1}{s ^{2} + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d s} ((s^{2} + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( s ^{2} + 4 ) ^{2}} \frac{d}{d s} (s^{2} + 4)

= - \frac{1}{( s ^{2} + 4 ) ^{2}} \frac{d}{d s} (s^{2} + 4)

\frac{d}{d s} (s^{2} + 4) = 2 s

= 2 (- \frac{1}{( s ^{2} + 4 ) ^{2}} \cdot 2 s)

Simplify

2 (- \frac{1}{( s ^{2} + 4 ) ^{2}} \cdot 2 s) : - \frac{4 s}{( s ^{2} + 4 ) ^{2}}

= - \frac{4 s}{( s ^{2} + 4 ) ^{2}}

sin (5 x^{2} - 3 x + 4)

y = 63

f (t) = \frac{t}{t ^{2} - 2}

y = sin^{2} (3 x + 4)

3 x - 2 y = lo g_{10} (3 x + 2 y)

What is the derivative of 2/((s^2+4)) ?
The derivative of 2/((s^2+4)) is -(4s)/((s^2+4)^2)
What is the first derivative of 2/((s^2+4)) ?
The first derivative of 2/((s^2+4)) is -(4s)/((s^2+4)^2)