What is the derivative of y=sin^2(3x+4) ?

The derivative of y=sin^2(3x+4) is 6sin(3x+4)cos(3x+4)

What is the first derivative of y=sin^2(3x+4) ?

The first derivative of y=sin^2(3x+4) is 6sin(3x+4)cos(3x+4)

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derivative of

y = sin^{2} (3 x + 4)

6 sin (3 x + 4) cos (3 x + 4)

Solution steps

\frac{d}{d x} (sin^{2} (3 x + 4))

Apply the chain rule:

2 sin (3 x + 4) \frac{d}{d x} (sin (3 x + 4))

= 2 sin (3 x + 4) \frac{d}{d x} (sin (3 x + 4))

\frac{d}{d x} (sin (3 x + 4)) = cos (3 x + 4) \cdot 3

= 2 sin (3 x + 4) cos (3 x + 4) \cdot 3

Simplify

= 6 sin (3 x + 4) cos (3 x + 4)

3 x - 2 y = lo g_{10} (3 x + 2 y)

x^{2} + 5 y^{2} = 5

3 + sin (y) = y - x^{3}

x^{2} + 2 x y = 3 y^{2}

x^{2} + y^{2} = 9

What is the derivative of y=sin^2(3x+4) ?
The derivative of y=sin^2(3x+4) is 6sin(3x+4)cos(3x+4)
What is the first derivative of y=sin^2(3x+4) ?
The first derivative of y=sin^2(3x+4) is 6sin(3x+4)cos(3x+4)