What is derivative of x^2+2xy=3y^2 ?

The answer to derivative of x^2+2xy=3y^2 is (dy)/(dx)=-(x+y)/(x-3y)

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derivative of x^2+2xy=3y^2

derivative of

x^{2} + 2 x y = 3 y^{2}

\frac{d y}{d x} = - \frac{x + y}{x - 3 y}

Solution steps

x^{2} + 2 x y = 3 y^{2}

Treat

y

y (x)

Differentiate both sides:

2 x + 2 (y + x \frac{d y}{d x}) = 6 y \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{x + y}{x - 3 y}

\frac{d y}{d x} = - \frac{x + y}{x - 3 y}

x^{2} + y^{2} = 9

2 x y - 4 y + 5 = 0

x = cos^{4} (t)

x^{4} + y^{4} = 4 a^{2} x^{3} y^{3}

(d^{2} + d) \cdot y = x^{2} + 2 x + 4

What is derivative of x^2+2xy=3y^2 ?
The answer to derivative of x^2+2xy=3y^2 is (dy)/(dx)=-(x+y)/(x-3y)