What is derivative of (d^2+d)*y=x^2+2x+4 ?

The answer to derivative of (d^2+d)*y=x^2+2x+4 is (dy)/(dx)=(2x+2)/(d^2+d)

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derivative of (d^2+d)*y=x^2+2x+4

derivative of

(d^{2} + d) \cdot y = x^{2} + 2 x + 4

\frac{d y}{d x} = \frac{2 x + 2}{d ^{2} + d}

Solution steps

(d^{2} + d) y = x^{2} + 2 x + 4

Treat

y

y (x)

Differentiate both sides:

(d^{2} + d) \frac{d y}{d x} = 2 x + 2

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 x + 2}{d ^{2} + d}

\frac{d y}{d x} = \frac{2 x + 2}{d ^{2} + d}

(d^{2} + d) y = x^{2} + 2 x + 4

x = e^{s i n (t^{2} - 4 t)}

(d^{2} + 1) \cdot y = x^{2} \cdot (cos (x))

x^{3} + y^{3} = 9

x^{2} + y^{2} - 3 x y = 1

What is derivative of (d^2+d)*y=x^2+2x+4 ?
The answer to derivative of (d^2+d)*y=x^2+2x+4 is (dy)/(dx)=(2x+2)/(d^2+d)