What is derivative of v=2-4t-6t^3 ?

The answer to derivative of v=2-4t-6t^3 is (dt)/(dv)=-1/(2(2+9t^2))

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derivative of v=2-4t-6t^3

derivative of

v = 2 - 4 t - 6 t^{3}

\frac{d t}{d v} = - \frac{1}{2 ( 2 + 9 t ^{2} )}

Solution steps

v = 2 - 4 t - 6 t^{3}

Treat

t

t (v)

Differentiate both sides:

1 = - 4 \frac{d t}{d v} - 18 t^{2} \frac{d t}{d v}

Isolate

\frac{d t}{d v} : \frac{d t}{d v} = - \frac{1}{2 ( 2 + 9 t ^{2} )}

\frac{d t}{d v} = - \frac{1}{2 ( 2 + 9 t ^{2} )}

4 y = - 8 x + 2 x + 0

y^{2} = x

x^{2} + y^{2} = 6 x + 4 y

x = \frac{u - 1}{2}

x = y^{2}

What is derivative of v=2-4t-6t^3 ?
The answer to derivative of v=2-4t-6t^3 is (dt)/(dv)=-1/(2(2+9t^2))