What is derivative of x+y=x^2y^2 ?

The answer to derivative of x+y=x^2y^2 is (dy)/(dx)=(2xy^2-1)/(1-2x^2y)

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derivative of x+y=x^2y^2

derivative of

x + y = x^{2} y^{2}

\frac{d y}{d x} = \frac{2 x y ^{2} - 1}{1 - 2 x ^{2} y}

Solution steps

x + y = x^{2} y^{2}

Treat

y

y (x)

Differentiate both sides:

1 + \frac{d y}{d x} = 2 x y^{2} + 2 y \frac{d y}{d x} x^{2}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 x y ^{2} - 1}{1 - 2 x ^{2} y}

\frac{d y}{d x} = \frac{2 x y ^{2} - 1}{1 - 2 x ^{2} y}

x^{2} - 10 x + y^{2} + 8 = 0

(a) y = e^{2} x + x

r = (t^{4} + 12) (t^{6} + 8)

\frac{x ^{m}}{a ^{m}} + \frac{y ^{m}}{b ^{m}} = 1

3 x^{3} y^{2} = 17

What is derivative of x+y=x^2y^2 ?
The answer to derivative of x+y=x^2y^2 is (dy)/(dx)=(2xy^2-1)/(1-2x^2y)