What is derivative of 3x^3y^2=17 ?

The answer to derivative of 3x^3y^2=17 is (dy)/(dx)=-(3y)/(2x)

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derivative of 3x^3y^2=17

derivative of

3 x^{3} y^{2} = 17

\frac{d y}{d x} = - \frac{3 y}{2 x}

Solution steps

3 x^{3} y^{2} = 17

Treat

y

y (x)

Differentiate both sides:

3 (3 x^{2} y^{2} + 2 y \frac{d y}{d x} x^{3}) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{3 y}{2 x}

\frac{d y}{d x} = - \frac{3 y}{2 x}

(x + 2 i) (y + 2 i) = - 1 + 8 i

x^{2} + y^{2} = 1

2 x + 25 y = 0

x^{2} y + y^{2} x = 6

x^{2} (x - 2 y) = x + 2 y

What is derivative of 3x^3y^2=17 ?
The answer to derivative of 3x^3y^2=17 is (dy)/(dx)=-(3y)/(2x)