What is derivative of y^2=4a(x+a) ?

The answer to derivative of y^2=4a(x+a) is (dy}{dx}=\frac{2a)/y

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derivative of y^2=4a(x+a)

derivative of

y^{2} = 4 a (x + a)

\frac{d y}{d x} = \frac{2 a}{y}

Solution steps

y^{2} = 4 a (x + a)

Treat

y

y (x)

Differentiate both sides:

2 y \frac{d y}{d x} = 4 a

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 a}{y}

\frac{d y}{d x} = \frac{2 a}{y}

x = \frac{( 1 + t ) ^{3}}{t ^{2}}

y^{2} = 2 x

x^{2} y^{2} = 1

x = (t^{2} + 1)^{\frac{1}{2}}

x + y - x^{3} y = 15

What is derivative of y^2=4a(x+a) ?
The answer to derivative of y^2=4a(x+a) is (dy}{dx}=\frac{2a)/y