What is derivative of x^2y^2=1 ?

The answer to derivative of x^2y^2=1 is (dy)/(dx)=-y/x

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derivative of x^2y^2=1

derivative of

x^{2} y^{2} = 1

\frac{d y}{d x} = - \frac{y}{x}

Solution steps

x^{2} y^{2} = 1

Treat

y

y (x)

Differentiate both sides:

2 x y^{2} + 2 y \frac{d y}{d x} x^{2} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{y}{x}

\frac{d y}{d x} = - \frac{y}{x}

x = (t^{2} + 1)^{\frac{1}{2}}

x + y - x^{3} y = 15

x = (1 - y^{2})^{\frac{1}{2}}

2 x^{2} + 2 y - 2 x y = 4

x^{2} + 2 x y = y^{2}

What is derivative of x^2y^2=1 ?
The answer to derivative of x^2y^2=1 is (dy)/(dx)=-y/x