What is derivative of s=(t^2+4)/2 ?

The answer to derivative of s=(t^2+4)/2 is (dt)/(ds)= 1/t

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derivative of s=(t^2+4)/2

derivative of

s = \frac{t ^{2} + 4}{2}

\frac{d t}{d s} = \frac{1}{t}

Solution steps

s = \frac{t ^{2} + 4}{2}

Treat

t

t (s)

Differentiate both sides:

1 = t \frac{d t}{d s}

Isolate

\frac{d t}{d s} : \frac{d t}{d s} = \frac{1}{t}

\frac{d t}{d s} = \frac{1}{t}

x y = y^{2}

x^{3} y^{2} - 2 y = 4

y + sin (y) = x^{2}

x^{2} - y^{2} = 2

x = tan^{2} (y)

What is derivative of s=(t^2+4)/2 ?
The answer to derivative of s=(t^2+4)/2 is (dt)/(ds)= 1/t