What is derivative of x=tan^2(y) ?

The answer to derivative of x=tan^2(y) is (dy)/(dx)= 1/(2tan(y)sec^2(y))

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derivative of x=tan^2(y)

derivative of

x = tan^{2} (y)

\frac{d y}{d x} = \frac{1}{2 tan ( y ) sec ^{2} ( y )}

Solution steps

x = tan^{2} (y)

Treat

y

y (x)

Differentiate both sides:

1 = 2 tan (y) sec^{2} (y) \frac{d y}{d x}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1}{2 tan ( y ) sec ^{2} ( y )}

\frac{d y}{d x} = \frac{1}{2 tan ( y ) sec ^{2} ( y )}

y^{2} = 40 x

x y = c^{2}

x^{y} = x^{3} + 2 sin (x)

1 - x^{3} = t^{2}

(x + y)^{2} = 4

What is derivative of x=tan^2(y) ?
The answer to derivative of x=tan^2(y) is (dy)/(dx)= 1/(2tan(y)sec^2(y))