What is derivative of (x+y)^2=4 ?

The answer to derivative of (x+y)^2=4 is (dy)/(dx)=-1

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derivative of (x+y)^2=4

derivative of

(x + y)^{2} = 4

\frac{d y}{d x} = - 1

Solution steps

(x + y)^{2} = 4

Treat

y

y (x)

Differentiate both sides:

2 (x + y) (1 + \frac{d y}{d x}) = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - 1

\frac{d y}{d x} = - 1

x^{2} - y^{2} = tan (x) y

x = \frac{y + 1}{y}

2 x^{3} + 4 x^{2} - y = x^{6}

y + 5 i = (2 x + i) (x + 2 i)

x = 70 y - y^{2}

What is derivative of (x+y)^2=4 ?
The answer to derivative of (x+y)^2=4 is (dy)/(dx)=-1