What is the integral of ((x+4))/((x^2+1)) ?

The integral of ((x+4))/((x^2+1)) is 1/2 ln|x^2+1|+4arctan(x)+C

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integral of ((x+4))/((x^2+1))

integral

\frac{( x + 4 )}{( x ^{2} + 1 )}

\frac{1}{2} ln x^{2} + 1 + 4 arctan (x) + C

Solution steps

\int \frac{x + 4}{x ^{2} + 1} d x

Expand

\frac{x + 4}{x ^{2} + 1} : \frac{x}{x ^{2} + 1} + \frac{4}{x ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 1} d x + \int \frac{4}{x ^{2} + 1} d x

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1

\int \frac{4}{x ^{2} + 1} d x = 4 arctan (x)

= \frac{1}{2} ln x^{2} + 1 + 4 arctan (x)

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 1 + 4 arctan (x) + C

sin^{2} (4 x)

\frac{- 2}{x ^{2}}

\frac{2}{e ^{x}}

t^{2} + 1

\frac{x ^{2}}{( x ^{2} - 1 )}

What is the integral of ((x+4))/((x^2+1)) ?
The integral of ((x+4))/((x^2+1)) is 1/2 ln|x^2+1|+4arctan(x)+C