What is the derivative of y=x^{9cos(x)} ?

The derivative of y=x^{9cos(x)} is 9x^{9cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of y=x^{9cos(x)} ?

The first derivative of y=x^{9cos(x)} is 9x^{9cos(x)}(-sin(x)ln(x)+(cos(x))/x)

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derivative of

y = x^{9 c o s (x)}

9 x^{9 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{9 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{9 c o s (x)} = e^{9 c o s (x) l n (x)}

= \frac{d}{d x} (e^{9 c o s (x) l n (x)})

Apply the chain rule:

e^{9 c o s (x) l n (x)} \frac{d}{d x} (9 cos (x) ln (x))

= e^{9 c o s (x) l n (x)} \frac{d}{d x} (9 cos (x) ln (x))

\frac{d}{d x} (9 cos (x) ln (x)) = 9 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{9 c o s (x) l n (x)} \cdot 9 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{9 c o s (x) l n (x)} = x^{9 c o s (x)}

= 9 x^{9 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

\int 2 - ∣ x ∣ d x

f (x) = \frac{1}{x}, (2, \frac{1}{2})

\frac{d}{d x} ((x^{3} + x^{2} - 2) (7 + x - x^{4}))

\int \frac{( 3 ( 4 u + 1 ) ^{\frac{1}{2}} )}{4} d u

\frac{d}{d x} (3 arccos (\frac{x}{2}))

What is the derivative of y=x^{9cos(x)} ?
The derivative of y=x^{9cos(x)} is 9x^{9cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of y=x^{9cos(x)} ?
The first derivative of y=x^{9cos(x)} is 9x^{9cos(x)}(-sin(x)ln(x)+(cos(x))/x)