What is the slope ofintercept (4,0),(-2,4) ?

The slope ofintercept (4,0),(-2,4) is y=-2/3 x+8/3

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slope ofintercept (4,0),(-2,4)

slope intercept

(4, 0), (- 2, 4)

y = - \frac{2}{3} x + \frac{8}{3}

Solution steps

Compute the slope

(4, 0), (- 2, 4) : m = - \frac{2}{3}

Compute the

y

intercept:

b = \frac{8}{3}

Construct the line equation

y = mx + b

where

m = - \frac{2}{3}

and

b = \frac{8}{3}

y = - \frac{2}{3} x + \frac{8}{3}

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{- t}, y (0) = 0, y^{^{'}} (0) = 2

\frac{d}{d x} (\frac{1}{sin ( x )})

f (x) = ln (5)

\int \frac{1}{5 s + 4} d s

x \to + 3 lim (3 x^{2} + 4 x - 1)

What is the slope ofintercept (4,0),(-2,4) ?
The slope ofintercept (4,0),(-2,4) is y=-2/3 x+8/3