What is the integral of (x/5)^2 ?

The integral of (x/5)^2 is (x^3)/(25)-(2x^3)/(75)+C

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integral of (x/5)^2

integral

(\frac{x}{5})^{2}

\frac{x ^{3}}{25} - \frac{2 x ^{3}}{75} + C

Solution steps

\int (\frac{x}{5})^{2} d x

Apply Integration By Parts

: \frac{x ^{3}}{25} - \int \frac{2 x ^{2}}{25} d x

= \frac{x ^{3}}{25} - \int \frac{2 x ^{2}}{25} d x

\int \frac{2 x ^{2}}{25} d x = \frac{2 x ^{3}}{75}

= \frac{x ^{3}}{25} - \frac{2 x ^{3}}{75}

Add a constant to the solution

= \frac{x ^{3}}{25} - \frac{2 x ^{3}}{75} + C

\frac{t}{( 1 + t ^{2} )}

(1 - x^{2})^{\frac{1}{2}}

x (2 - x)^{3}

\frac{x}{( x ^{2} + 1 ) ^{2}}

\frac{1}{sin ^{4} ( x )}

What is the integral of (x/5)^2 ?
The integral of (x/5)^2 is (x^3)/(25)-(2x^3)/(75)+C