What is the integral of (2-5)/(x^2) ?

The integral of (2-5)/(x^2) is 3/x+C

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integral of (2-5)/(x^2)

integral

\frac{2 - 5}{x ^{2}}

\frac{3}{x} + C

Solution steps

\int \frac{2 - 5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= (2 - 5) \cdot \int \frac{1}{x ^{2}} d x

Simplify

= (- 3) \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= (- 3) (- \frac{1}{x})

Simplify

(- 3) (- \frac{1}{x}) : \frac{3}{x}

= \frac{3}{x}

Add a constant to the solution

= \frac{3}{x} + C

sin^{7} (x) cos^{5} (x)

e^{z} (z + 1)

(x - 11)^{7}

\frac{1}{x ^{2} ( x + 1 ) ^{2}}

\frac{( x ^{2} )}{3}