What is the integral of 1/((x^3-1)^2) ?

The integral of 1/((x^3-1)^2) is

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integral of 1/((x^3-1)^2)

integral

\frac{1}{( x ^{3} - 1 ) ^{2}}

- \frac{2}{9} ln ∣ x - 1 ∣ + \frac{1}{9} ln 4 x^{2} + 4 x + 4 + \frac{2}{9 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{3 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{9 3} sin (2 arctan (\frac{1}{3} (2 x + 1))) - \frac{1}{9 ( x - 1 )} - \frac{1}{6 ( x ^{2} + x + 1 )} - \frac{1}{9 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1)))) + C

Solution steps

\int \frac{1}{( x ^{3} - 1 ) ^{2}} d x

Take the partial fraction of

\frac{1}{( x ^{3} - 1 ) ^{2}} : - \frac{2}{9 ( x - 1 )} + \frac{1}{9 ( x - 1 ) ^{2}} + \frac{2 x + 3}{9 ( x ^{2} + x + 1 )} + \frac{x + 1}{3 ( x ^{2} + x + 1 ) ^{2}}

= \int - \frac{2}{9 ( x - 1 )} + \frac{1}{9 ( x - 1 ) ^{2}} + \frac{2 x + 3}{9 ( x ^{2} + x + 1 )} + \frac{x + 1}{3 ( x ^{2} + x + 1 ) ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int \frac{2}{9 ( x - 1 )} d x + \int \frac{1}{9 ( x - 1 ) ^{2}} d x + \int \frac{2 x + 3}{9 ( x ^{2} + x + 1 )} d x + \int \frac{x + 1}{3 ( x ^{2} + x + 1 ) ^{2}} d x

\int \frac{2}{9 ( x - 1 )} d x = \frac{2}{9} ln ∣ x - 1 ∣

\int \frac{1}{9 ( x - 1 ) ^{2}} d x = - \frac{1}{9 ( x - 1 )}

\int \frac{2 x + 3}{9 ( x ^{2} + x + 1 )} d x = \frac{1}{9} (ln 4 x^{2} + 4 x + 4 - \frac{2}{3} arctan (\frac{2 x + 1}{3}) + 23 arctan (\frac{1}{3} (2 x + 1)))

\int \frac{x + 1}{3 ( x ^{2} + x + 1 ) ^{2}} d x = \frac{1}{3} (8 (- \frac{1}{4 ( 4 x ^{2} + 4 x + 4 )} - \frac{1}{24 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1))))) + \frac{2}{3 3} (2 arctan (\frac{2 x + 1}{3}) + sin (2 arctan (\frac{2 x + 1}{3}))))

= - \frac{2}{9} ln ∣ x - 1 ∣ - \frac{1}{9 ( x - 1 )} + \frac{1}{9} (ln 4 x^{2} + 4 x + 4 - \frac{2}{3} arctan (\frac{2 x + 1}{3}) + 23 arctan (\frac{1}{3} (2 x + 1))) + \frac{1}{3} (8 (- \frac{1}{4 ( 4 x ^{2} + 4 x + 4 )} - \frac{1}{24 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1))))) + \frac{2}{3 3} (2 arctan (\frac{2 x + 1}{3}) + sin (2 arctan (\frac{2 x + 1}{3}))))

Simplify

- \frac{2}{9} ln ∣ x - 1 ∣ - \frac{1}{9 ( x - 1 )} + \frac{1}{9} (ln 4 x^{2} + 4 x + 4 - \frac{2}{3} arctan (\frac{2 x + 1}{3}) + 23 arctan (\frac{1}{3} (2 x + 1))) + \frac{1}{3} (8 (- \frac{1}{4 ( 4 x ^{2} + 4 x + 4 )} - \frac{1}{24 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1))))) + \frac{2}{3 3} (2 arctan (\frac{2 x + 1}{3}) + sin (2 arctan (\frac{2 x + 1}{3})))) : - \frac{2}{9} ln ∣ x - 1 ∣ + \frac{1}{9} ln 4 x^{2} + 4 x + 4 + \frac{2}{9 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{3 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{9 3} sin (2 arctan (\frac{1}{3} (2 x + 1))) - \frac{1}{9 ( x - 1 )} - \frac{1}{6 ( x ^{2} + x + 1 )} - \frac{1}{9 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1))))

= - \frac{2}{9} ln ∣ x - 1 ∣ + \frac{1}{9} ln 4 x^{2} + 4 x + 4 + \frac{2}{9 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{3 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{9 3} sin (2 arctan (\frac{1}{3} (2 x + 1))) - \frac{1}{9 ( x - 1 )} - \frac{1}{6 ( x ^{2} + x + 1 )} - \frac{1}{9 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1))))

Add a constant to the solution

= - \frac{2}{9} ln ∣ x - 1 ∣ + \frac{1}{9} ln 4 x^{2} + 4 x + 4 + \frac{2}{9 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{3 3} arctan (\frac{1}{3} (2 x + 1)) + \frac{2}{9 3} sin (2 arctan (\frac{1}{3} (2 x + 1))) - \frac{1}{9 ( x - 1 )} - \frac{1}{6 ( x ^{2} + x + 1 )} - \frac{1}{9 3} (2 arctan (\frac{1}{3} (2 x + 1)) + sin (2 arctan (\frac{1}{3} (2 x + 1)))) + C

\frac{( e ^{x} + e ^{- x} )}{2}

\frac{2 x}{( x ^{2} + 1 ) ^{2}}

y^{2} x^{3}

\frac{1}{( x ^{2} - 3 )}

lo g_{10} (x^{2} + y^{2})