What is the integral of sin^2(x/2) ?

The integral of sin^2(x/2) is 1/2 (x-sin(x))+C

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integral of sin^2(x/2)

integral

sin^{2} (\frac{x}{2})

\frac{1}{2} (x - sin (x)) + C

Solution steps

\int sin^{2} (\frac{x}{2}) d x

Rewrite using trig identities

= \int \frac{1}{2} (1 - cos (x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 - cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d x - \int cos (x) d x)

\int 1 d x = x

\int cos (x) d x = sin (x)

= \frac{1}{2} (x - sin (x))

Add a constant to the solution

= \frac{1}{2} (x - sin (x)) + C

\frac{( 1 + x )}{( 1 + x ^{2} )}

y^{- 1}

f (x) = (x^{2} + 2 x + 5)^{\frac{1}{2}}

x \frac{cosh ( x )}{( sinh ( x ) ) ^{2}}

\frac{- 2}{( u ^{2} + u )}

What is the integral of sin^2(x/2) ?
The integral of sin^2(x/2) is 1/2 (x-sin(x))+C