What is the integral of (e^{-t})*(1/t) ?

The integral of (e^{-t})*(1/t) is \Ei(-t)+C

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integral of (e^{-t})*(1/t)

integral

(e^{- t}) \cdot (\frac{1}{t})

Ei (- t) + C

Solution steps

\int e^{- t} \frac{1}{t} d t

Simplify

e^{- t} \frac{1}{t} : \frac{e ^{- t}}{t}

= \int \frac{e ^{- t}}{t} d t

Apply u-substitution

: \int \frac{e ^{u}}{u} d u

= \int \frac{e ^{u}}{u} d u

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= Ei (u)

Substitute back

u = - t

= Ei (- t)

Add a constant to the solution

= Ei (- t) + C

x^{2} + a^{2}

(\frac{1}{x - 1})^{\frac{1}{2}}

\frac{10}{x ^{3}}

3 x^{5} - 8 x^{4}

\frac{2 x ^{2}}{( x ^{2} + 1 )}

What is the integral of (e^{-t})*(1/t) ?
The integral of (e^{-t})*(1/t) is \Ei(-t)+C