What is the integral of 1/(cos^2(1-2x)) ?

The integral of 1/(cos^2(1-2x)) is 1/2 tan(-1+2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(cos^2(1-2x))

integral

\frac{1}{cos ^{2} ( 1 - 2 x )}

\frac{1}{2} tan (- 1 + 2 x) + C

Solution steps

\int \frac{1}{cos ^{2} ( 1 - 2 x )} d x

Factor

1 - 2 x : - (- 1 + 2 x)

= \int \frac{1}{cos ^{2} ( - ( - 1 + 2 x ) )} d x

Simplify

\frac{1}{cos ^{2} ( - ( - 1 + 2 x ) )} : sec^{2} (- 1 + 2 x)

= \int sec^{2} (- 1 + 2 x) d x

Apply u-substitution

: \int sec^{2} (u) \frac{1}{2} d u

= \int sec^{2} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{2} tan (u)

Substitute back

u = - 1 + 2 x

= \frac{1}{2} tan (- 1 + 2 x)

Add a constant to the solution

= \frac{1}{2} tan (- 1 + 2 x) + C

\frac{1}{2 x ^{2} y}

x^{4} e^{x}

(1 + x)^{\frac{1}{4}}

e^{(8 x)^{2}}

ln (1 - x)

What is the integral of 1/(cos^2(1-2x)) ?
The integral of 1/(cos^2(1-2x)) is 1/2 tan(-1+2x)+C