What is the integral of f(x)= 1/(x^{1/2)} ?

The integral of f(x)= 1/(x^{1/2)} is 2x^{1/2}+C

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integral of f(x)= 1/(x^{1/2)}

integral

f (x) = \frac{1}{x ^{\frac{1}{2}}}

2 x^{\frac{1}{2}} + C

Solution steps

\int \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 x^{\frac{1}{2}}

Add a constant to the solution

= 2 x^{\frac{1}{2}} + C

\frac{x + 1}{3 x + 2}

sin^{6} (x) cos^{4} (x)

\frac{( 1 - cos ( x ) ) ^{2}}{sin ^{2} ( x )}

3^{- x}

\frac{arctan ( x )}{x ^{2}}

What is the integral of f(x)= 1/(x^{1/2)} ?
The integral of f(x)= 1/(x^{1/2)} is 2x^{1/2}+C