What is the integral of (x^{-2})/(-2) ?

The integral of (x^{-2})/(-2) is 1/(2x)+C

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integral of (x^{-2})/(-2)

integral

\frac{x ^{- 2}}{- 2}

\frac{1}{2 x} + C

Solution steps

\int \frac{x ^{- 2}}{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{- 2} \cdot \int x^{- 2} d x

Simplify

= (- \frac{1}{2}) \cdot \int x^{- 2} d x

Apply the Power Rule

: - \frac{1}{x}

= (- \frac{1}{2}) (- \frac{1}{x})

Simplify

(- \frac{1}{2}) (- \frac{1}{x}) : \frac{1}{2 x}

= \frac{1}{2 x}

Add a constant to the solution

= \frac{1}{2 x} + C

3 x^{2} + 8 x + 3

\frac{x - 2}{x + 2}

\frac{1}{( y ^{2} + 1 ) ^{2}}

\frac{1}{2 sin ^{2} ( x )}

\frac{x ^{2}}{x + 1}

What is the integral of (x^{-2})/(-2) ?
The integral of (x^{-2})/(-2) is 1/(2x)+C