What is the integral of 1/(2sin^2(x)) ?

The integral of 1/(2sin^2(x)) is -1/2 cot(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(2sin^2(x))

integral

\frac{1}{2 sin ^{2} ( x )}

- \frac{1}{2} cot (x) + C

Solution steps

\int \frac{1}{2 sin ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= \frac{1}{2} (- cot (x))

Simplify

= - \frac{1}{2} cot (x)

Add a constant to the solution

= - \frac{1}{2} cot (x) + C

\frac{x ^{2}}{x + 1}

\frac{1}{2 ( x )}

(4 x^{2} + 5)^{4}

(x + 1) sin (x^{2} + 2 x + 3)

x \cdot (x^{2} + 1)^{\frac{1}{2}}

What is the integral of 1/(2sin^2(x)) ?
The integral of 1/(2sin^2(x)) is -1/2 cot(x)+C