What is the limit as x approaches 0 of ln(x^2+1) ?

The limit as x approaches 0 of ln(x^2+1) is 0

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limit as x approaches 0 of ln(x^2+1)

x \to 0 lim (ln (x^{2} + 1))

0

Solution steps

x \to 0 lim (ln (x^{2} + 1))

Plug in the value

x = 0

= ln (0^{2} + 1)

Simplify

ln (0^{2} + 1) : 0

= 0

y^{^{''}} + 3 y^{^{'}} - 4 y = 0

\int (cos (x)) (tan (x)) d x

x \to 3 - lim (\frac{x - 3}{x - 3})

\frac{d}{d x} (2 (3 - 8 x)^{3})

What is the limit as x approaches 0 of ln(x^2+1) ?
The limit as x approaches 0 of ln(x^2+1) is 0