What is the integral of (2y^2)/(x^3) ?

The integral of (2y^2)/(x^3) is 2/(x^3)*(y^3)/3+C

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integral of (2y^2)/(x^3)

integral

\frac{2 y ^{2}}{x ^{3}}

\frac{2}{x ^{3}} \cdot \frac{y ^{3}}{3} + C

Solution steps

\int \frac{2 y ^{2}}{x ^{3}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{x ^{3}} \cdot \int y^{2} d y

Apply the Power Rule

: \frac{y ^{3}}{3}

= \frac{2}{x ^{3}} \cdot \frac{y ^{3}}{3}

Add a constant to the solution

= \frac{2}{x ^{3}} \cdot \frac{y ^{3}}{3} + C

x^{5} (1 - x^{2})^{0.5}

(x^{2} - 1)^{2}

(1 - 4 x) (1 + x)

3 - 2 (x)^{- 1}

\frac{1}{( x )}

What is the integral of (2y^2)/(x^3) ?
The integral of (2y^2)/(x^3) is 2/(x^3)*(y^3)/3+C